16t^2+64t+64=0

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Solution for 16t^2+64t+64=0 equation: 



16t^2+64t+64=0

a = 16; b = 64; c = +64;
Δ = b2-4ac
Δ = 642-4·16·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-64}{32}=-2$

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